Volume emptied V = 500 x 10^-6 m3 ± 25 x 10^-6 m3
Height of water to the hole h = 0.145 m ± 0.001 m
We have the best estimate of actual time to empty volume = 16.72 s ± 0.572 sHeight of water to the hole h = 0.145 m ± 0.001 m
We empty the bucket of water for 6 times.
Run | Time to empty (s) |
1 | 17.05 s ± 0.01 s |
2 | 17.34 s ± 0.01 s |
3 | 17.2 s ± 0.01 s |
4 | 16.5 s ± 0.01 s |
5 | 15.51 s ± 0.01 s |
6 | 16.74 s ± 0.01 s |
Diameter of hole = 0.0052 m ± 0.1 m
Area of drain hole = Ï€(0.0052 m/2 ± 0.1)^2 = 2.123 x 10^-5 m2 ± 0.2 m2
Acceleration due to gravity g = 9.81 ms-2
We have the theoretical time to empty volume:Area of drain hole = Ï€(0.0052 m/2 ± 0.1)^2 = 2.123 x 10^-5 m2 ± 0.2 m2
Acceleration due to gravity g = 9.81 ms-2
ttheoretical = V/(A(2gh)^1/2) = 13.96 s ± 3.093 s
We compare the theoretical time and actual time to empty volume:
Run | Theoretical time (s) | Actual Time (s) | Does Actual time agress within uncertainty? |
1 | 13.96 ± 3.093 | 17.05 ± 0.01 | Yes |
2 | 13.96 ± 3.094 | 17.34 ± 0.01 | No |
3 | 13.96 ± 3.095 | 17.20 ± 0.01 | No |
4 | 13.96 ± 3.096 | 16.50 ± 0.01 | Yes |
5 | 13.96 ± 3.097 | 15.51 ± 0.01 | Yes |
6 | 13.96 ± 3.098 | 16.74 ± 0.01 | Yes |
We need also compare the calculated and given diameter.
The calculated diameter = 0.0052 m ± 1.045 x 10-3 m
The given diameter = 0.0052 m ± 0.1 m
The given diameter = 0.0052 m ± 0.1 m
Conclusion:
By comparing the theoretical time and actual time to empty volume, we have the 4 experimental values agree with the theoretical time out of 6 trials, which means the we can successful approach the theoretical time in the change of 2/3. Also, the calculated diameter is in the range of the given diameter, which shows the set up of experiment approaches the theoretical fluid model. We thus successful set up the fluid dynamic model as the experimental data are closed to theoretical data.
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